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Convert newton into dyne....

Convert newton into dyne.

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Dimensional formula of force is `M^(1) L^(1) T^(-2)`
`IN = n "dynes" rArr n = N//"dynes"`
`therefore n_(2) = n_(1) [(M_1)/(M_2) ]^(1) [(L_1)/(L_2) ]^(1) [(T_1)/(T_2) ]^(-2)`
`rArr n= [(1kg)/(1g) ] [(1m)/(1cm)]^(1) [(1s)/(1s)]^(-2) ((n_2)/(n_1) = n)`
`rArr n= [(1000g)/(1g) ] [(100 cm)/(1 cm) ]^(1) [(1s)/(1s) ]^(-2)`
`rArr n= [ 1000] xx [100]^(1) xx [1]^(2) = 0^(7)`
`therefore1` newton `=10^(7)` dynes
Alternate Method : `[FJ] = [MLT^(-2) ],`
1 newton = 1 (kg) (m) `(s)^(-2)`
`= 1 xx (10^(3) g) (10^(2) cm) (s)^(2) = 10^(5) (g) (cm) (s)^(-2)`
1 newton `= 10^(5)` dynes
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