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The potential energy of a particle varie...

The potential energy of a particle varies with distance x from a fixed origin as `V = (Asqrt(x))/(x+B)` where A and B are constants. The dinmensions of AB are

A

`M^(1) L^(5//2) T^(-2)`

B

`M^(1) L^(2) T^(-2)`

C

`M^(3//2) L^(5//2) T^(-2)`

D

`M^(1) L^(7//2) T^(-2)`

Text Solution

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The correct Answer is:
D
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