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Temperature of 1 mole of an ideal gas is...

Temperature of 1 mole of an ideal gas is increased from 300 K to 310 K under isochoric process. Heat supplied to the gas in this process is Q = 25 R, where R = universal gas constant. What amount of work has to be done by the gas if temperature of the gas decreases from 310 K to 300 K adiabatically?

Text Solution

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`DeltaQ=nC_(v)DeltaT`
`:.25R =(1)(C_(v)) (310-300)or C_(v)=(5)/(2) R`
i.e. gas is diatomic or `gamma=1.4`
Now work done in adiabatic process
`W=(nR(T_(1)-T_(2)))/(gamma-1)=((1)(R )(310-300))/(1.4-1) =25R`
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