Draw the P-T and V-T diagrams for an isobaric process of expansion, corresponding to n moles of an ideal gas at a pressure `P_(0)`, from `V_(0)` to `2V_(0)`.

Explanation

For the graph of P versus T the variation is a straight line normal to the pressure axis, the temperature varying from `T_(1)` to `T_(2)` as shown figure.
From the gas equation PV = nRT

we have, `V = ((nR)/(P_(0)))T or V prop T`
At `V=V_(0) , T_(1) =(P_(0)V_(0))/(nR) and " at " V=2V_(0), T_(2) =(2P_(0) V_(0))/(nR)`

From the graph of V versus T, the equation `V=((nR)/(P_(0)))T or V = kT` shows that the volume varies directly, as the temperature (Charles. law). So, the graph is a straight line inclined to the (V-T) axis, and passing through the origin (when produced) as shown in figure.