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A monoatomic gas undergoes a process giv...

A monoatomic gas undergoes a process given by 2dU + 3d W = 0, then what is the process

Text Solution

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`dQ = dU + dW`
`rArr dQ = dU - (2dU)/(3) =(dU)/(3) = (1)/(3) nC_(v)dT`
`=(1)/(3)n.(3)/(2)RdT=(nRdT)/(2) rArr C=(1)/(n)(dQ)/(dT)=(R )/(2)`
It is not isobaric as C is not equal to `(5R)/(2)`
It is not adiabatic as `c ne 0`
It is not isothermal as `c ne oo` so it is an polytropic process.
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