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A refrigerator, whose coefficient of per...

A refrigerator, whose coefficient of performance K is 5, extracts heat from the cooling compartment at the rate of 250 J per cycle.
(a) How much work per cycle is required to operate the refrigerator cycle ?
(b) How much heat per cycle is discharged to the room which acts as the high temperature reservoir?

Text Solution

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(a) As coefficient of performance of a refrigerator is defined as
`K=Q_(L)//W,"So "W=(Q_(L))/(K)=(250)/(5)=50J`
(b) As `Q_(H)=Q_(L)+W" so "Q_(H)=250+50=300J`
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