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Efficiency of a heat engine whose sink i...

Efficiency of a heat engine whose sink is at temperature of 300 K is 40% . To increase the efficiency to 60 % keeping the sink temperature same, the source temperature must be increased by

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`(T_(2))/(T_(1))=1-eta=1-(40)/(100)=(3)/(5)`
`rArr T_(1)=(5)/(3)T_(2) rArr T_(1)=(5)/(3)xx300=500K`
New efficiency `eta=60%`
`(T_(2))/(T_(1))=1-eta=1-(60)/(100)=(2)/(5)" "T_(1)=(5)/(2)xx300=750K`,
`DeltaT=750-500=250K`
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