A copper block of mass 5 kg slides down along a rough inclined plane of inclination `30^(@)` with a constant speed. The increase in the temperature of the block as it slides down through 100cm assuming that the loss of mech anical energy goes into copper block as thermal energy. (specific heat of copper 420 J `kg^(-1)k^(-1) g=10ms^(-2)`)

Options

A. `1.19xx10^(-3)""^(@)C`
B. `2.38xx10^(-3)""^(@)C`
C. `1.19 xx 10^(-2)""^(@)C`
D. `2.38 xx 10^(-2) ""^(@)C`

Answer

C