Home
Class 12
PHYSICS
The binding energies per nucleon for deu...

The binding energies per nucleon for deuteron `(._1H^2)` and helium `(._2He^4)` are 1.1 MeV and 7.0 MeV respectively. Calculate the energy released, when two deuterons fuse to form a helium nucleus.

Text Solution

Verified by Experts

The fusion reaction is `2(""_(1)H^(2)) rarr ""_(2)He^(4)+Q`
Q = Total binding energy of the product `""_(2)He^(4)` - Total binding energy of reactant i.e. , two deuterons.
`= 4 xx7.0 - 4 xx 1.1 = 28.0 - 4.4`
= 23 . 6 MeV
Promotional Banner

Similar Questions

Explore conceptually related problems

The binding energy par nucleon for deuterium (""_(1)^(2)H) and helium (""_(4)^(2)He) are 1.1 MeV and 7.0 MeV respectively. The energy released when two deutrons fuse to form a helium nucleus (""_(4)^(2)He) is K(10^(7)) MeV, where K= ……… (nearly)

The binding energies per nucleon for deuterium and helium are 1.1 MeV and 7.0 MeV respectively. What energy in joules will be liberated when 10^(6) deuterons take part in the reaction.

It has been estimated that the total power radiated by the sun is 3.8 xx 10^(26) J per second . The source of energy of stars is a thermonucleur fission reaction . Energy released in the process of fusion is due to mass defect . Q = Delta mc^(2) B.E. per nucleon of ""_(1)^(2) H and ""_(2)^(4) He and 1.1 MeV and 7 MeV respectively . If two deutrons nuclei react to form a single helium nucleus , then the energy released is :

The binding energies of nuclei X and Y are E_1 and E_2 respectively. Two atoms of X fuse to give one atom of Y and an energy Q is released. Find Q