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The kinetic energy of alpha - particles ...

The kinetic energy of `alpha` - particles emitted in the decay of `""_(88)Ra^(226)` into `""_(86)Rn^(222)` is measured to be 4.78 MeV. What is the total disintegration energy or the 'Q - value of this process ?

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The standard relation between the kinetic energy of the `alpha ` - particle `(KE_a)` and the Q - value (or total disintegration energy) is
`KE_(a) = ((A-4)/A) . Q" " Q = ((A)/(A-4)).KE_(a)`
`=((226)/(226-4))xx4.78MeV= (226)/(222) xx 4.78 MeV`
`Q = 4.865MeV ~~4.87MeV`
Notice that `KE_(alpha)` is very close to (but smaller than) Q`
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