Let Q be the set of all rational number ...

Let Q be the set of all rational number in `[0, 1]` and `f:[0, 1]rarr[0, 1]` be defined by `f(x)={{:(x," for ", x in Q),(1-x," for ", x cancel(in)Q):}` Then the set `S={x in [0, 1] (fof)(x)=x}` is equal to

A

Q

B

`[0, 1]-Q`

C

`(0, 1)`

D

[0, 1]

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The correct Answer is:

D

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