Let f: { - pi/3, (2pi)/(3)} rarr [0, 4] ...

Let `f: { - pi/3, (2pi)/(3)} rarr [0, 4]` be a function defined as `f(x)=sqrt(3) sin x - cos x + 2`. Then `f^(-1)(x)` is given by

A

`sin^(-1)((x-2)/(2))- pi/6`

B

`sin^(-1)((x-2)/(2))+pi/6`

C

`(2pi)/(3) + cos^(-1)((x-2)/(2))`

D

none of these

Verified by Experts

The correct Answer is:

B

Similar Questions

Explore conceptually related problems

If f(x) = |cos x - sin x| , then f^(1)(pi/4) =

Define f(x) = (1)/(2)[|sinx|+sin x], 0 lt x le 2pi . Then f is

If A={3, 0, 1, 2} and f:A rarr B is an onto function defined by f(x)=3x-5, then B=

The domain of the function f defined by f(x)= sqrt(4-x) + (1)/(sqrt(x^(2)-1)) is equal to

If A={0,pi/6,pi/4,pi/3,pi/2} and f:Ato B is a surjection defined by f(x)=cosx then find B.

If f: R rarr [0, oo) is a function such that f(x-1)+f(x+1)=sqrt(3)f(x) , and f(x) is periodic then its period is