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For x != 0, 1, define f(1)(x)=x, f(2)(x)...

For `x != 0, 1`, define `f_(1)(x)=x, f_(2)(x)=1/x, f_(3)(x)=1-x, f(5) (x)=(x-1)//x, f_(6)(x)=x//(x-1)`
This family of functions is closed under composition that is , the composition of any two of these functions is again one of these.
Let H be a function such that `f_(4)OH=f_(5)`. Then H is equal to

A

`f_(1)`

B

`f_(2)`

C

`f_(3)`

D

`f_(4)`

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The correct Answer is:
D
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