For `x != 0, 1`, define `f_(1)(x)=x, f_(2)(x)=1/x, f_(3)(x)=1-x, f(5) (x)=(x-1)//x, f_(6)(x)=x//(x-1)`
This family of functions is closed under composition that is , the composition of any two of these functions is again one of these.
Let G be a function such that `GOf_(3)=f_(6)`. Then G is equal to

Options

A. `f_(6)`
B. `f_(4)`
C. `f_(5)`
D. `f_(3)`

Answer

B