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phi(x) = f(x)g(x) and f'(x)g'(x) = k, th...

`phi(x) = f(x)g(x) and f'(x)g'(x) = k`, then `(2k)/(f(x)g(x))` =

A

`(phi''(x))/(phi(x)) - (f''(x))/(f(x)) - (g''(x))/(g(x))`

B

`(phi''(x))/(phi(x)) + (f''(x))/(f(x)) + (g''(x))/(g(x))`

C

`(phi''(x))/(phi(x)) + (f''(x))/(f(x)) - (g''(x))/(g(x))`

D

`(phi''(x))/(phi(x)) - (f''(x))/(f(x)) + (g''(x))/(g(x))`

Text Solution

Verified by Experts

The correct Answer is:
B
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