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f'(x) = cancel(O)(x) and cancel(O)'(x) =...

`f'(x) = cancel(O)(x)` and cancel(O)'(x) = f(x)` for all x. Also `f(3) = 5` and f'(3) = 4` , then the value of `[f(10)^2 - [cancel(O)(10)]^2` is

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