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y = log^(n)x x where log^(n) means log.l...

`y = log^(n)x` x where `log^(n)` means log.log.log ....(repeated n times) then `x.logx.log^2x.log^3x-log^(n-1)x,(dy)/(dx)`=

A

`log x `

B

`log^(n) x`

C

`1/(logx)`

D

1

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The correct Answer is:
D
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