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Two oxide of metal M have 27.6% and 30% ...

Two oxide of metal M have `27.6%` and `30%` oxygen by weight. If the formula of the first oxide is `M_(3)O_(4)` what is the formula of second oxide?

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Oxide(A): Oxygen 27.6% 4.O. atoms , Meta 72.6%3 .M. atoms
Oxide (B) : Oxygen 30% Metal 70%
Number of .O. atoms `=(30)/(27.6)xx4=4.35`
Number of .M. atoms `=(70)/(72.4)xx3=2.9`
Ratio of M and O atoms in oxide B =2.9:4.35=2:3
Formula of the second oxide is `M_(2)O_(3)`
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