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A compound has molar of 98.98g. The anal...

A compound has molar of 98.98g. The analysis gave 24.27%C, 4.07%H and 71.6% CI. Determine the molecular formula of alkane from which the chlorinated compound is obtained.

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`C : H : CI = (24.27)/(12) : (4.07)/(1) : (71.6)/(35.5) = 1 : 2 : 1 `
Empirical formula is ` CH_(2)CI`
Number of repeating empirical units in the molecular formula `= ("Molecular formula mass" )/("Empirical formula mass")=(98.98)/(49.5) = 2`
Molecular formula is `C_(2)H_(4)CI_(2)`
The formula of alkane from which the halogenated compound is obtained `= C_(2)H_(6)`.
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