0.4 mole of orthophosphoric acid and 1.0 mole of calcium hydroxide were allowed to react. Calculate the maximum number of moles of calcium phosphate formed. 

Explanation

The storichiometric equation is `3CaI(OH)_(2)+2H_(3)PO_(4)toCa_(3)(PO_(4))_(2)+3H_(2)O`
3 moles of `Ca(OH)_(2)` = 2 moles of `H_(2)PO_(4)`
1 mole of `Ca(OH)_(2)` =0.67 mole of `H_(3)PO_(4)`
`H_(3)PO_(4)` is the imiting reagent . Hence, salt formed is dependent on the availability of acid only.
2 moles of `H_(3)PO_(4)` =1 mole of `Ca_(3)(PO_(4))_(2)`
0.4 moles of `H_(3)PO_(4)` =?
Number of moles of calicum phosphate formed `= 0.4xx(1)/(2) =0.2 ` mole