60mL of pure ozone is heated and then colled. The increase in the volume is 10mL. Determine the percentage volume of ozone decomposed into oxygen.

Explanation

The balanced equations for the decomposed of ozone is
`2O_(3)(g)to3O_(2)(g)`
`2 vol " " 3vol "Gay-Lussac.s coefficients"`
`60mL " " "0mL at start"`
`60-2x " " 3x "after the reaction"`
Total volume of the mixture after the reaction =60-2x+3x=60+10
Solving, x=10
Volume of `O_(3)` decomposed =20mL
Percentage volume of `O_(3)` decomposed `=(20/(60)xx100=33.3%)`