Specific heat of a metal is 0.115 cal `K^(-1)` . If the weight percentage of metal in metal oxide is 77.28, determine the valency of metal.

Explanation

Approximate atomic mass of metal `=(6.4)/("specific heat")=(6.4)/(0.115)=55.65`
In 100 g of metal oxide, weight of metal =77.28g
Weight of oxygen =22.22g
`(W_(i))/(W_(2))=(E_(1))/(E_(2))`
Equivalent weight of oxygen =8
Equivalent weight of metal `=(77.28)/(22.22)xx8=27.82`
Valency of meta `=("approximate atomic weight ")/("equivalent weight") =(55.62)/(27.82)=2`