How many moles are present in 1500mL of semi molar sucrose solutions? What is the weight of solute in the solution?

Explanation

Number of mole of solute present in V Lit solution is given as
VM, where V=1.5lit and M =0.5mol `L^(-1)`
Number of moles of solute `= 1.5xx0.5=0.75`
Gram molecular weight (GMW) of sucrose = 342g
Weight of solute = number of moles GMW `=0.75xx342=256.5g`