Two grams of pure caustic soda is present dissolved in 1.5 Lit solution. If 10mL of this is diluted to 150mL. What is the normality of diluted base?

Explanation

Number of moles of caustic soda
`("weight")/(GMW)=(2)/(40)=0.05`
Normality `=(0.05)/(1.5)=0.0333eq L^(-1)`
Equation for dilution `=V_(1)N_(1) -V_(2)N_(2)`
Normality of dilute solution `=N_(2)=(V_(1)N_(1))/(V_(2))=(10xx0.0333)/(150)=0.00222eq L^(-1)`