X. and .Y. are two different solutions o...

X. and .Y. are two different solutions of hydrochloric acid with concentrations 5M and 2M respectively. If one litre of 3M hydrochloric acid is to be prepared by mixing only X and Y calculate their volumes.

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Volume of solution .X. is V mL
Volume of solution .Y. is (1000-V)mL
Molarity desired to be obtained =3M
Volume desired to be obtained =1000mL
`M=(Vxx5(1000-V)2)/(1000)=3`
Solving, V=333.3ml
The volumes of Solutions .X. and .Y. are to be mixed are respectively 333.3mL and 666.7mL.

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