Home
Class 11
CHEMISTRY
0.25g of an organic compound an analysis...

0.25g of an organic compound an analysis by Duma,s method gave 32cc nitrogen at STP. What is the weight percentage of nitrogen in the given compound?

Text Solution

Verified by Experts

The correct Answer is:
16
Promotional Banner

Topper's Solved these Questions

  • STOICHIOMETRY

    AAKASH SERIES|Exercise EXERCISE -1.1.6|4 Videos
  • STOICHIOMETRY

    AAKASH SERIES|Exercise EXERCISE -1.1.7|11 Videos
  • STOICHIOMETRY

    AAKASH SERIES|Exercise EXERCISE -1.1.4|19 Videos
  • STATES OF MATTER

    AAKASH SERIES|Exercise OBJECTIVE EXERCISE -3|19 Videos

Similar Questions

Explore conceptually related problems

0.28g of an organic compound in Dumas method liberated 22.4 ml of nitrogen at STP. The percentage of nitrogen in the compound is

0.66 g of a compound gave 112 ml of nitrogen at STP in the Dumas method. The percentage of Nitrogen in the compound is

0.246 g of the organic compound gave 22.4 cm^(3) of nitrogen gas at STP as determined by Dumas method. The percent of nitrogen in the compound is

0.156g of an organic compound in carius tube method gave 0.235g of silver iodide. Calculate the percent weight of halogen in the compound .

If 0.75 g of an organic compound in Kjeldahl's method neutralized 30 ml of 0.25N- H_(2)SO_(4) , the percentage of nitrogen in the compound is

In Dumas method , 0.3 g of an organic compound gave 45 ml of nitrogen at STP. The percentage of nitrogen is

The hetero elements in organic compound are nitrogen, halogen, sulphur and phosphorousd, Nitrogen is estimated by Duma's method (or) Kjeldahl's method. The other hetero elements are estimated using Carius method. 0.25 g of an organic compound gave 22.4 ml. of N_(2) at STP by Duma's method. The percentage of Nitrogen in the compound is