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12 ml of a gaseous mixture of hydrocarbo...

12 ml of a gaseous mixture of hydrocarbons `C_(n)H_(2n)` and `C_(n)H_(2n+2)` (n is same for both ) required exactly 57mL of oxygen for combustion . If the volume of carbondioxide obtained under similar conditions is 36mL, What is the volume ratio of hydrocarbons in the given mixture.

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The correct Answer is:
1:1
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