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A 25mL of NO(3)^(-) Solution was treated...

A 25mL of `NO_(3)^(-)` Solution was treated with excess Al. The ammonia gas is passed into 50mL of 0.15N HCl. Excess unreacted acid HCl is back titrated with 32.1mL 0.1N NaOH solution. Calculate the molarity of `NO_(3)^(-)` in the original solution.

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The correct Answer is:
`0.172mo^(-1)`
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