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Total number of sulphate ions present in...

Total number of sulphate ions present in 3.92 g of chromic sulphate is (Cr=52, S=32, O=16)

A

`1.8xx10^(23)`

B

`1.8xx10^(23)`

C

`1.2xx10^(21)`

D

`6xx10^(23)`

Text Solution

Verified by Experts

The correct Answer is:
A
Chromic sulphate `Cr_(2)(SO_(4))_(3)`
molecular weight = 392
`392g Cr_(2)(SO_(4))_(3)-6.023xx10^(23)`
molecules `-3xx6.023xx10^(23)SO_(4)^(--)` ions
`3.92g Cr_(2)(SO_(4))_(3)`_________?
`(3.92xx3xx6.023xx10^(23))/(392)=1.8xx10^(22)`
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