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The weight of 600 ml of a mixture of ozo...

The weight of 600 ml of a mixture of ozone and oxygen is 1 gm at STP. The volume of oxygen in the mixture is

A

200 ml

B

500 ml

C

400 ml

D

300 ml

Text Solution

Verified by Experts

The correct Answer is:
C
`M_(mix)=M`. Then `(1)/(M)=n`
`"volume"_("STP")=(1)/(M)xx22400=600impliesM=(112)/(3)`
If moles of `O_(2)=x % O_(3)=y`
then `M=(32x+48y)/(x+y)=(112)/(3)`
`implies 96x+144y=112x+112y`
`(x)/(y)=(1)/(2)`
`therefore V_(O_(2))=(1)/(3)xx600=200mL`
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