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60g of a compound on analysis gave C=24g...

60g of a compound on analysis gave `C=24g, H=4g and O=32g.` Its empirical formula is

A

`C_(2)H_(4)O_(2)`

B

`CH_(2)O`

C

`CH_(2)O_(2)`

D

`C_(2)H_(2)O`

Text Solution

Verified by Experts

The correct Answer is:
B
`{:(,"C",,"H",,"O"),(,24,:,4,:,32),("Moles =",2,:,4,:,2),(,1,:,2,:,1):}` implies `CH_(2)O`
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