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H(3)PO(4)+2KOHrarrK(2)HPO(4)+2H(2)O Ba...

`H_(3)PO_(4)+2KOHrarrK_(2)HPO_(4)+2H_(2)O`
Based on the above reaction equivalent weight of `H_(2)PO_(4)` is 

A

196

B

98

C

49

D

`32.67`

Text Solution

Verified by Experts

The correct Answer is:
C
n-factor = No. of `H^(+)` replaced = 2
`implies E=(M)/(2)=(98)/(2)=49`
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