The equivalent weight of glucose in the ...

The equivalent weight of glucose in the reaction `C_(6)H_(12)O_(6)+6O_(2)rarr 6CO_(2)+6H_(2)O` is
[M is molecular weight]

A

M

B

`M//2`

C

`M//24`

D

2M

Verified by Experts

The correct Answer is:

C

Change in oxidation state = 4
No. of C = 6 implies n-factor = 24

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