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K(4)[Fe(CN)(6)] is converted into CO(3)^...

`K_(4)[Fe(CN)_(6)]` is converted into `CO_(3)^(-2)`, `Fe^(+3)` ions and `NO_(3)^(-)` ions. Here_____________

A

N. is reduced

B

C. is oxidised

C

Iron is oxidised

D

Eq.wt `("Formula.wt")/(61)`

Text Solution

Verified by Experts

The correct Answer is:
B, C, D
`{:(Fe^(++)rarrFe^(+++),"(OX)",1xx1=1),(overset(+2)(CN^(-))rarroverset(+4)(CO_(3)^(-2)),"(OX)",6xx2=12),(overset((-3))(CN^(-))rarroverset((+5))(NO_(3)^(-)),"(OX)",6xx8=48),(,,61):}`
n factor = 61
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