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4Mg+10HNO(3)to4Mg(NO(3))(2)+NH(4)NO(3)+3...

`4Mg+10HNO_(3)to4Mg(NO_(3))_(2)+NH_(4)NO_(3)+3H_(2)O`. In this reaction

A

96 gms magnesium can reduce one mole of `HNO_(3)`

B

Equivalent weight of reduced `HNO_(3)` is `(1)/(8)th` of its molecular weight

C

Entire `HNO_(3)` involved in the reaction is reduced

D

`HNO_(3)` is reduced to the best possible extent

Text Solution

Verified by Experts

The correct Answer is:
A, B, D
Out of 10 moles of `HNO_(3)`, only 1 mole gets reduced by 4 moles of Mg.
n - f of reduced `HNO_(3)=(+5-(-3))=8`
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