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4.4 gms of a hydrocarbons one combustion...

4.4 gms of a hydrocarbons one combustion produced 6.72 L of `CO_(2)` at STP and sufficient water vapour that can generate 0.4gms of `H_(2)` with excess Na. The hydrocarbon is .x. times heavier than `CO_(2)`. What is .x.?

Text Solution

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The correct Answer is:
1
`2Na+2H_(2)Orarr2NaOH+H_(2)`
`36g___________2g`
`7.2g___________0.4g`
`22.4LCO_(2)-STP-44g`
`6.72LCO_(2)-STP-13.2g`
`underset("propane")(C_(3)H_(8))+5O_(2)rarr3CO_(2)+4H_(2)O`
`44g_______132g_______72g`
`4.4g_______13.2g_______7.2g`
`therefore x=(44)/(44)=1`
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