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What is ("mol. Wt")/("Eq. wt") of FeC(2)...

What is `("mol. Wt")/("Eq. wt")` of `FeC_(2)O_(4)` getting converted into `Fe^(+3)` and `CO_(2)`?

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The correct Answer is:
3
`Fe^(++)+C_(2)O_(4)^(--)rarrFe^(+++)+2CO_(2)+3e^(-)` n factor = 3
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