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In the reaction 4A+2B+3CrarrA(4)B(2)C(3)...

In the reaction `4A+2B+3CrarrA_(4)B_(2)C_(3)`, what will be the number of moles of product formed, starting from one mole of A, 0.6 moles of B and 0.72 moles of C

A

`0.25`

B

`0.3`

C

`0.24`

D

`2.32`

Text Solution

Verified by Experts

The correct Answer is:
C

`4A+2B+3CrarrA_(4)B_(2)C_(3)`
`(1)/(4),(0.6)/(2)(0.72)/(3)`
`(0.72)/(3)lt(1)/(4)lt(0.6)/(2)`
implies C is limiting reagent
implies amount of product = `(0.72)/(3)=0.24`
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