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The number of moles of Fe(2)O(3) formed ...

The number of moles of `Fe_(2)O_(3)` formed when 5.6 lit of `O_(2)` reacts with 5.6g of Fe? 

A

`0.125`

B

`0.01`

C

`0.05`

D

`0.10`

Text Solution

Verified by Experts

The correct Answer is:
C
`4Fe+3O_(2)rarr2FeO_(3)`
`3xx22.4Lit O_(2)rarr4xx56gmFe`
`5.6 lit. O_(2)rarr=(56)/(3)gmFe`
implies Fe is limiting reagent
`therefore` moles of `Fe_(2)O_(3)=(0.1xx2)/(4)=0.05`
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