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70 g of a sample of magnesite on treatme...

70 g of a sample of magnesite on treatment with excess of HCl gave 11.2 L of `CO_(2)` at STP. The percentage purify of the sample

A

80

B

70

C

60

D

50

Text Solution

Verified by Experts

The correct Answer is:
C
`underset(42g)underset(84g)(MgCO_(3))+2HClrarrMgCl_(2)+H_(2)O+underset(11.2L)underset(22.4L)(CO_(2))`
% purity `MgCO_(3)=(42)/(70)xx100=60`
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