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NH(3) is formed in the following steps ...

`NH_(3)` is formed in the following steps
I. `Ca+2CrarrCaC_(2)` 50% yield
II. `CaC_(2)+N_(2)rarrCaCN_(2)+C` 100% yield
III. `CaCN_(2)+3H_(2)Orarr2NH_(3)+CaCO_(3)` 50% yield
To obtain 2 moles `NH_(3)`, calcium required is

A

1 mol

B

2 mol

C

3 mol

D

4 mol

Text Solution

Verified by Experts

The correct Answer is:
D
`Ca+2CrarrCaC_(2)`
`100rarr50`
`CaC_(2)+N_(2)rarrCaCN_(2)+C`
`50rarr50`
`CaCN_(2)+3H_(2)Orarr2NH_(3)+CaCO_(3)`
`50rarr100xx(50)/(100)=50`
`therefore CararrNH_(3)`
`100rarr50`
`?rarr2 =4mol`
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