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40 ml of a hydrocarbon undergoes combust...

40 ml of a hydrocarbon undergoes combustion in 260 ml oxygen and gives 160 mlof `CO_(2)`. If all volumes are measured under similar conditions of temperature and pressue, the formula of the hydrocarbon is

A

`C_(3)H_(8)`

B

`C_(4)H_(8)`

C

`C_(6)H_(14)`

D

`C_(4)H_(10)`

Text Solution

Verified by Experts

The correct Answer is:
D
`C_(4)H_(10)+(13)/(2)O_(2)rarr4CO_(2)+5H_(2)O`
`40 ml-260 ml-160 ml`
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