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In a reaction vessel, 100 g H(2) and 100...

In a reaction vessel, `100 g H_(2)` and 100 g `Cl_(2)` are mixed and suitable conditions are provided for the reaction: `H_(2(g))+Cl_(2(g))to2HCl_((g))`
The amount of HCl formed in this reaction (at 100% yield) will be

A

`50g`

B

`97.2g`

C

`46g`

D

`64g`

Text Solution

Verified by Experts

The correct Answer is:
B
`underset(2g)(H_(2(g)))+underset(71g)(Cl_(2(g)))rarrunderset(73g)(2HCl_((g)))`
`100g underset("reagent")underset("limiting")(100g)`
100% yield of HCl `=(100xx73)/(71)=102.8g`
90% yield of HCl = `(90)/(100)xx102.8=92.53g`
`H_(2)` reacted = 2.8 gm
`therefore H_(2)` unreacted = `100-2.8=97.2g`
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