Home
Class 11
CHEMISTRY
Match type of the salt formed with the a...

Match type of the salt formed with the appropriate reaction.
`{:(,"Column-I (Reaction)",,"Column-II (Type of Salt)"),("A)","1 mole of oxalic acid +1 mole of NaOH","P)","Mixed salt"),("B)","1 mole of "H_(3)PO_(2)+1" mole KOH","Q)","Basic salt"),("C)","1 mole of "Ca(OH)_(2)+1" mole of HCl","R)","Acid salt"),("D)","Dry slaked lime "+Cl_(2),"S)","Normal salt"):}`

Text Solution

Verified by Experts

The correct Answer is:
A-R; B-S; C-Q; D-P

A) `rarrunderset("COOH ")underset("| ")(COONa)` Acidic salt
B) `rarrKH_(2)PO_(2)` Normal salt
C) `rarrCa(Cl)OH` Basic salt
D) `rarrCaOCl_(2)` Mixed salt (Bleaching powder)
Promotional Banner

Similar Questions

Explore conceptually related problems

{:(,"Column-I",,"Column-II"),("A)","One gram molecules of oxygen gas","P)","one mole of "H_(2)),("B)","Gram molar volume of "H_(2),"Q)","one mole of "O_(2)),("C)","44 gm of "CO_(2),"R)","22.4lit at STP"),("D)","18 gm water","S)",3N_(A)" atoms"):}

{:("Column-I","Column-II"),("A) 16g of "O_(2),"P) 1gm atom of O"),("B) Gram molar volume of "H_(2)O,"Q) 22.4 lit at STP"),("C) 18 g of "H_(2)O,"R) 18 ml"),("D) 1/2 mole "O_(2)+1" gm atom of "H_(2),"S) 11.2 lit at STP"):}

{:("Column-I (mixed in equal volumes)" ,, "Column -II (Nature of solution)") , ( "A)" 0.2 M HCN + 0.1 M KOH ,, "P) Strong base"), ("B)" 0.2 M HCl + 0.1 M KCN ,, "Q) basic buffer") , ("C)" 0.2 M NH_(3) + 0.1 M HCl ,, "R) acidic buffer"), ("D)" 0.2 M KOH + 0.1 M NH_(4) Cl ,, "S) Strong acid"):}

Match the concentration terms with the factors affecting the concentration. {:("Column-I","Column-II"),("A) Molarity (M)","P) Temperature"),("B) Molality (m)","Q) Pressure"),("C) Mole fraction (X)","R) Dilution"),("D) Normality","S) Volume"):}

{:("Column-I","Column-II"),("A) 1.2g of carbon","P) "4.8xx10^(23)" atoms"),("B) 3g of "CO_(2),"Q) "9.034xx10^(23)" atoms"),("C) 11.2 L "CO_(2)" at S.T.P.","Q) 0.1 moles"),("D) 0.2 moles "NH_(3),"S) "9.64xx10^(24)" electrons"):}

{:("Column-I ","Column-II "),("A) Atm L mol"^(-1),"P)" a//Rb),("B) " sqrt((2RT)/(M)), "Q)" a//b),("C) Boyle temperature ","R)" V_m),("D) Volume of one mole","S) "u_(MP)):}

{:(,"Column-I",,"Column-II"),("A)",N_(2),"P)","40% carbon by mass"),("B)",CO,"Q)","Empirical formula "CH_(2)O),("C)",C_(6)H_(12)O_(6),"R)","Vapour density : 14"),("D)",CH_(3)COOH,"S)",14N_(A)" electrons in a mole"):}

{:("LIST - 1","LIST-2"),("A) 1 mole of","1) 44 g of oxide"),("lead nitratenitrous",),("B) 1 mole of ammonium","2) 28 g of nitrogen"),("nitrate",),("C) 1 mole of","3) 48 g of oxygen"),("ammonium nitrite",),("D) 1 mole of potassium","4) 92 g of "NO_(2)),("chlorate",),(,"5) 46 g of "NO_(2)):} The correct match is

When 0.1 mole of BaCl_(2) is treated with 0.5 mole of Na_(3)PO_(4) , the maximum number of moles of Barium phosphate formed is