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The percentage by volume of C(3)H(8) in ...

The percentage by volume of `C_(3)H_(8)` in a gaseous mixture of `C_(3)H_(8),CH_(4)andCO` is 20. When 10 ml of the mixture is burnt in excess of `O_(2)`, the volume of `CO_(2)` produced is `2xml`. Find the value of .x..

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The correct Answer is:
7
20% of 10 ml =2 ml
Let volume of `CH_(4)=x`
`implies CO=(8-x)ml`
`{:(C_(3)H_(8)+5O_(2),rarr,3CO_(2)+4H_(2)O),("2 ml",rarr,"6 ml"),(CH_(4)+2O_(2),rarr,CO_(2)+2H_(2)O),("x ml",rarr,"x ml"),(CO+(1)/(2)O_(2),rarr,CO_(2)),((8-x)ml,rarr,(8-x)ml):}`
`V_(CO_(2))=6+x+(8-x)=14ml`
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