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How much Ca(NO(3))(2) in mg must be pres...

How much `Ca(NO_(3))_(2)` in mg must be present in 50 ml of a solution with 2.35 ppm of Ca?

A

`0.1175`

B

`770.8`

C

`4.7`

D

`0.48`

Text Solution

Verified by Experts

The correct Answer is:
D
Water density 1g/ml
`10^(6)g` (`10^(6)` ml) water contains 2.35g Ca
50ml (50g) water contains `(50xx2.35)/(10^(6))gCa`
`=(50xx2.35)/(10^(6))xx10^(3)mgCa=0.1175gCa`
`40gCa-164gCa(NO_(3))_(2)`
`0.1175Ca-0.48g Ca(NO_(3))_(2)`
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