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0.1 mole of KMnO(4) present in 500 ml so...

0.1 mole of `KMnO_(4)` present in 500 ml solution got converted into `K_(2)MnO_(4)`. The concentration of `KMnO_(4)` is

A

0.2 M

B

0.2 N

C

1 N

D

0.04 N

Text Solution

Verified by Experts

The correct Answer is:
A, B
n-factor = `1,M=(0.1)/(0.5)=0.2M=0.2N`
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