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An aqueous glucose solution contains 180...

An aqueous glucose solution contains 180 ppm glucose. If one .ml. of the solution is mixed with 99ml water, the molarity of the resultant solution is `x xx10^(-y)`. What is y? (d=1 gm/cc)

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The correct Answer is:
5
`(w_(1))/(w_(2))xx10^(6)=180(w_(2)=V_("sol.(ml)"))`
`M=(w_(1))/(180xx((w_(2))/(1000)))=(w_(1))/(w_(2))xx(10^(3))/(180)`
`=(180)/(10^(6))xx(10^(3))/(180)=10^(-3)M`
`M_(1)V_(1)=M_(2)V_(2)implies1xx10^(-3)=100xxM_(2)`
`M_(2)=10^(-5)`
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