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An equimolar mixture of Na(2)C(2)O(4) an...

An equimolar mixture of `Na_(2)C_(2)O_(4)` and `H_(2)C_(2)O_(4)` required `V_(1)L` of `0.1 M KMnO_(4)` in acidic medium for complete oxidation. The same amount of the mixture required `V_(2)L` of 0.1 M NaOH for neutralization. The ratio of `V_(1)` to `V_(2)` is

A

`1:2`

B

`2:1`

C

`2:5`

D

`5:2`

Text Solution

Verified by Experts

The correct Answer is:
C
Let no. of moles of `Na_(2)C_(2)O_(4)` & `H_(2)C_(2)O_(4)=a`
Eqts of `(Na_(2)C_(2)O_(4))` + Eqts of `H_(2)C_(2)O_(4)`
= Eqts of `KMnO_(4)`
`(axx2)+(axx2)=0.1xx5xxV_(1)`
`4a=0.1xx5V_(1)" "…..(1)`
Eqts of `(Na_(2)C_(2)O_(4)) +` Eqts of `H_(2)C_(2)O_(4)`
= Eqts of NaOH
`axx2=0.1xx1xxv_(2)" ".....(2)`
On solving (1), (2) implies `(V_(1))/(V_(2))=2:5`
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