Home
Class 11
CHEMISTRY
3 moles of a mixture of FeSO(4) and Fe(2...

3 moles of a mixture of `FeSO_(4)` and `Fe_(2)(SO_(4))_(3)` required 100 mL of 2 M `KMnO_(4)` solution in acidic medium. Hence, mole fraction of `FeSO_(4)` in the mixture is

A

`(1)/(3)`

B

`(2)/(3)`

C

`(2)/(5)`

D

`(3)/(5)`

Text Solution

Verified by Experts

The correct Answer is:
A

Let moles of `FeSO_(4)=x`
eq. `FeSO_(4)` = eq. `KMnO_(4)`
`x xx1=0.1xx2xx5impliesx=1`
`therefore` mole fraction =1/3
Promotional Banner

Similar Questions

Explore conceptually related problems

2 mole, equimolar mixture of Na_(2)C_(2)O_(4) and H_(2)C_(2)O_(4) required V_1 L of 0.1 M KMnO_4 in acidic medium for complete oxidatiion. The same amount of the mixture required V_2 L of 0.1 M NaOH for neutralization. The ratio of V_(1) " to "V_2 is x:y, then the value of x + y is (x and y are integers)

An equimolar mixture of Na_(2)C_(2)O_(4) and H_(2)C_(2)O_(4) required V_(1)L of 0.1 M KMnO_(4) in acidic medium for complete oxidation. The same amount of the mixture required V_(2)L of 0.1 M NaOH for neutralization. The ratio of V_(1) to V_(2) is

10 g sample of H_(2)O_(2) just decolorised 100 ml of 0.1 M KMnO_(4) in acidic medium % by mass of H_(2)O_(2) in the sample is

Moles of KHC_(2)O_(4) (potassium acid oxalate) required to reduce 100 mL of 0.02M KMnO_(4) in acidic medium (to Mn^(2+) ) is

The number of moles of H_(2)O_(2) needed to reduce 2 mole of KMnO_(4) in acidic medium is.

The weight of oxalic acid required to reduce 80 ml of 0.4 M KMnO_(4) in acidic medium is

1 mol of equimolar mixture of ferric oxalate and ferrous oxalate will require x mol of KMnO_(4) in acidic medium for complete oxidation. X is

The number of moles of MnO_(4)^(-) and Cr_(2)O_(7)^(-2) separately required to oxidise 1 mole of FeC_(2)O_(4) each in acidic medium respectively